task_sem3_2.1

#include <stdio.h>
#include <math.h>
#include "optim.h"

#define LEFT 0.0
#define RIGHT 5.0
#define EVALUATE 1e-10

double f(double x) {
    numcount1++;
    return -(pow(sin(x), 6.0) * tan(1.0 - x) * exp(30.0 * x));
}

double f1(double x, double *d) {
    numcount1++;
    *d = exp(30.0 * x) * pow(sin(x), 5.0) * (sin(x) / pow(cos(1.0 - x), 2.0) - 6.0 * tan(1.0 - x) * (5.0 * sin(x) + cos(x)));
    return -(pow(sin(x), 6.0) * tan(1.0 - x) * exp(30.0 * x));
}

int main(int argc, char *argv[]) {
    double ax, bx, cx;
    double fa, fb, fc;
    double x;

    ax = LEFT; bx = RIGHT;

    numcount1 = 0;
    minbrack(f, &ax, &bx, &cx, &fa, &fb, &fc);
    x = golden(f, ax, bx, cx, 1e-10);
    printf("golden\tx = %e | max(f) = %e | funcs = %d | iters = %d\n", x, -f(x), numcount1, itercount1);

    numcount1 = 0;
    x = fmin1(f, LEFT, RIGHT, 0.0);
    printf("fmin\tx = %e | max(f) = %e | funcs = %d | iters = %d\n", x, -f(x), numcount1, itercount1);

    numcount1 = 0;
    x = davidon(f1, LEFT, RIGHT, EVALUATE, 1e-10);
    printf("davidon\tx = %e | max(f) = %e | funcs = %d | iters = %d\n", x, -f(x), numcount1, itercount1);

    return 0;
}