SUM

#include <iostream>
using namespace std;
int main(){
    int a[35], n, sum(0);
    cin >> n;
    for(int i = 1; i <= n; ++i)
        cin >> a[i],
        sum += a[i];
    for(int i = 1; i <= n; ++i)
        if(a[i] >= (double) sum * 1.0 / n)
            cout << a[i] << " ";
}