дз 1

#include <stdio.h>
#include <math.h>

int main()
{
    int n = 0;
    int r = 0;
    int t = 0;

    scanf("%d", &n);

    for (; n; n /= 10)
    {
        const int d = n % 10;
        r += d != 1 ? d * (int)pow(10, t++) : 0;
    }

    printf("%d", r);
    return 0;
}