content_of_an_address_v1.c

/*

    content_of_an_address_v1.c

    Task from Sunshine S
    https://web.facebook.com/sunshines13

    https://web.facebook.com/groups/543431102664524/?post_id=1174495746224720&comment_id=1174746769532951&reply_comment_id=1175294896144805&notif_id=1591153540531865&notif_t=group_comment&ref=notif

    What is the command if I want to see content of an address?
    Say, I want to see the content of FFFF?

    You must know what type of variable is on that address. If it is int then
    int *ip=FFFF;
    printf("%d", *ip);

    But, you cant read all memory. Read this
    https://gribblelab.org/CBootCamp/7_Memory_Stack_vs_Heap.html

    https://stackoverflow.com/questions/32914298/print-value-and-address-of-pointer-defined-in-function


    You can find all my C programs at Dragan Milicev's pastebin:

    https://pastebin.com/u/dmilicev

*/

#include <stdio.h>

int main(void)
{
    int n = 5;
    int *pn;

    pn = &n;

    printf("\n On hexadecimal address %p is value n = %d \n", (void *)pn, *pn );

    printf("\n On decimal address %d is value n = %d \n", (void *)pn, *pn );


    pn = (void *)0x0022FF18;    // here write hexadecimal address which is on your screen

    printf("\n On hexadecimal address %p is value n = %d \n", (void *)pn, *pn );


    pn = (void *)2293528;       // here write decimal address which is on your screen

    printf("\n On decimal address %d is value n = %d \n", (void *)pn, *pn );




    return 0;

} // main()