Lucky Division

#include<stdio.h>
int main()
{
    int n,r,temp,ct=0;
    scanf("%d",&n);
    temp=n;
    while(n!=0)
    {
        r=n%10;
        n=n/10;
        if(r!=7&&r!=4)
            ct++;
    }
    if(ct==0||temp%4==0||temp%7==0)
        printf("YES\n");
    else
        printf("NO\n");
    return 0;
}