Transformari din zecimal in binar,octa si hexa

#include <stdio.h>
#include <conio.h>
#include <stdlib.h>

void inHexa(long int n) {
    int i = 1, j, temp, r, q;
    char numarHexadecimal[100];

    q = n;
    while (q != 0) {
        temp = q % 16;

        //Convertim numarul intreg in caracter

        if (temp < 10) {
            temp = temp + 48;
        }
        else {
            temp = temp + 55;
        }
        numarHexadecimal[i++] = temp;
        q = q / 16;
    }
    printf("\nNumarul %d in hexadecimal este ", n);
    for (j = i - 1; j > 0; j--)
        printf("%c.", numarHexadecimal[j]);

}

void inBinar(int n) {           // prin recursivitate, convertim numarul in baza 2
    if (n / 2 != 0) {
        inBinar(n / 2);
    }
    printf("%d", n % 2);
}

void main() {
AGAIN:

    long int n;
    char conversie, continuare;
    int i = 1, j, temp;
    char numarHexadecimal[100];

    printf("Introduceti un numar: \n");
    scanf_s("%ld", &n);

    printf("Introduceti tasta: \n~\"o\" - octal \n~\"h\" - hexadecimal:\n~\"b\" - binar\n");

    conversie = _getch();

    if (conversie == 'o') {
        printf("\nNumarul %d in octal este %o .", n, n);
    }
    else
        if (conversie == 'h') {
            inHexa(n);
        }
        else if (conversie == 'b') {
            printf("\nNumarul %d in binar este: ", n);
            inBinar(n);
        }
        else {
            printf("\nVa rog sa reintroduceti tasta!");

            conversie = getchar();
        }

        printf("\n\nDoriti sa reluati programul?(y/any key)");
        continuare = _getch();
        if (continuare == 'y') {
            system("CLS");
            goto AGAIN;
        }
        else {
            exit(0);
        }

}