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Mar 28th, 2010
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  1. int balioztau()
  2. {
  3.   int i;
  4.  
  5.   gakoa[22] = 0;
  6.   for ( i = 0; i <= 22; i += 2 )
  7.   {
  8.     if ( gakoa[i] != pasahitza[i / 2] )
  9.       return 0;
  10.   }
  11.   return 1;
  12. }
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