pyg9of12.py

pyg = 'ay'

original = raw_input('Enter a word:')
word = original.lower()
first = word[0]
new_word = word + pyg

if len(original) > 0 and original.isalpha():
    if first in ["a","e","i","o","u"]:
        print new_word
    else:
        print word[1:] + first + pyg
else:
    print 'empty'

""" Although it seems to print correctly in the output box I receive an error message keeping me from going further with the course. (I also posted this to the course forum)

Oops, try again! Your word started with a consonant, but "dogay" was printed instead of "ogday". Make sure the correct value is stored in "new_word".

In the output window I get ogday, the desired result.

Is there anything apparent that would cause this?"""

"""mokomull> rfmonk: If I had to guess, the CodeAcademy thing doesn't actually look at what you printed, and instead looks at whatever's in the new_word variable.  I would do `new_word = word[1:] + first + pyg` and `new_word = "empty"` (and replace `print new_word` with `pass`) inside the conditional, and just do "print new_word" all the way at the end, outside of the if statements.

ok so when I declared my variables I changed

new_word = word + pyg
to
new_word = word[1:] + first + pyg and new_word = "empty"
print new_word changed to pass
&
print new_word outside the conditional at the end like:
else:
    print new_word
see paste pyg9of12.2.py"""