Rank of a Permutation

from math import factorial

def find_rank(s):
    n = len(s)
    rank = 0
    chars = list(s)

    for i in range(n):
        count = 0
        for j in range(i + 1, n):
            if chars[j] < chars[i]:
                count += 1
        rank += count * factorial(n - i - 1)

    return rank + 1

# Test Case
print(find_rank("123456798"))  # Output: 2