## Range

r = range(5)
print(r)

for item in range(5):
  print("Vysakh")

s = 0
for item in range(6):
  s += item
print(s)

for item in range(2,15,2):
  print(item)

s = 'aaaaa'
for item in s:
  print('hi')

l = [6,3,1,2,9,5]
x = max(l)
print(x)

s = [6,3,1,2,9,5]
l = min(s)
print(l)

## Counter using digit

s = 'abcaabcdeefghhhi'
c = {}
for item in s:
  if item not in c:
    c[item] = 1
print(c)

s = 'abcaabcdeefghhhi'
c = {}
for item in s:
  if item not in c:
    c[item] = 1
  else:
    c[item] = c[item] + 1
print(c)

## Listing a directory

! ls -l /etc/apache2

import os
r = os.listdir('/etc/apache2')
print(r)

import os
for item in os.listdir('/etc'):
  if item.endswith('.conf'):
    print(item)

##------------------------------------ Task 2 ------------------------------------------------

## 1] dict to list of list

d = {'sam': 200, 'kevin': 400, 'john': 300 , 'devon':100 }
l = []

for item in d:
   k = d[item]
   c = item.split()
   if k not in c:
    c.append(k)
    l.append(c)
print(l)

ans] [['sam', 200], ['kevin', 400], ['john', 300], ['devon', 100]]


## 2] find the highest ranked employee name.

ll = [ ["alex",10] , ["sam",8] , ["kevin",5], ["john",3]]
y = 0

for item in ll:
  name = item[0]
  rank = item[1]
  if rank > y:
    y = rank
    z = name
print(z)

ans] alex

## 3]  find the sum of odd numbers between 1-100 using range function and forloop

s = 0
for item in range(1,101,2):
  s += item
print(s)

ans] 2500

## 4] - find the occurrence of words.

s = """The OS includes some common elastic core components, like the GNU tools,
among others. These kick tools give the user a way to manage the resources
provided by the kernel, Kernel apple install additional axe knee software, configure performance
and security Knife settings, and more. eye keep All of odd these tools bundled together
make up the knee umbrella keen axe functional kick operating system.  Because Linux is an open source
OS, combinations of kick elastic software enrich can vary between Linux distributions."""

s = s.replace(",","")
s = s.lower().replace(".","").split()
y = {}
for item in s:
  if item not in y:
    y[item] = 0
  if item in y:
    y[item] = y[item] + 1
print(y)

ans]
{'the': 6, 'os': 2, 'includes': 1, 'some': 1, 'common': 1, 'elastic': 2, 'core': 1, 'components': 1, 'like': 1, 'gnu': 1, 'tools': 3, 'among': 1, 'others': 1, 'these': 2, 'kick': 3, 'give': 1, 'user': 1, 'a': 1, 'way': 1, 'to': 1, 'manage': 1, 'resources': 1, 'provided': 1, 'by': 1, 'kernel': 2, 'apple': 1, 'install': 1, 'additional': 1, 'axe': 2, 'knee': 2, 'software': 2, 'configure': 1, 'performance': 1, 'and': 2, 'security': 1, 'knife': 1, 'settings': 1, 'more': 1, 'eye': 1, 'keep': 1, 'all': 1, 'of': 2, 'odd': 1, 'bundled': 1, 'together': 1, 'make': 1, 'up': 1, 'umbrella': 1, 'keen': 1, 'functional': 1, 'operating': 1, 'system': 1, 'because': 1, 'linux': 2, 'is': 1, 'an': 1, 'open': 1, 'source': 1, 'combinations': 1, 'enrich': 1, 'can': 1, 'vary': 1, 'between': 1, 'distributions': 1}


## 5 - add the words to dict.


s = """The OS includes some common elastic core components, like the GNU tools,
among others. These kick tools give the user a way to manage the resources
provided by the kernel, Kernel apple install additional axe knee software, configure performance
and security Knife settings, and more. eye keep All of odd these tools bundled together
make up the knee umbrella keen axe functional kick operating system.  Because Linux is an open source
OS, combinations of kick elastic software enrich can vary between Linux distributions."""

s = s.replace(",","")
s = s.lower().replace(".","").split()
words = {"a":[] , "e":[] , "i":[] , "o":[] , "u":[]}

for item in s:
  if item[0] in 'a,e,i,o,u':
    for x in words:
      if x == item[0]:
        words[x].append(item)
print(words)

ans]
{'a': ['among', 'a', 'apple', 'additional', 'axe', 'and', 'and', 'all', 'axe', 'an'], 'e': ['elastic', 'eye', 'elastic', 'enrich'], 'i': ['includes', 'install', 'is'], 'o': ['os', 'others', 'of', 'odd', 'operating', 'open', 'os', 'of'], 'u': ['user', 'up', 'umbrella']}


## 6] list the directory "/etc" find the total number of files ends with ".conf" extension.

import os
for item in os.listdir('/etc'):
  if item.endswith('.conf'):
    print(item)

ans]
rsyslog.conf
gai.conf
xattr.conf
ld.so.conf
adduser.conf
ucf.conf
fuse.conf
resolv.conf
nsswitch.conf
libaudit.conf
ca-certificates.conf
deluser.conf
nftables.conf
e2scrub.conf
host.conf
sudo_logsrvd.conf
pam.conf
sudo.conf
sysctl.conf
mke2fs.conf
debconf.conf
logrotate.conf
​