KRITSADA

Number of Divider Nanobit

Feb 16th, 2022
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Python 0.26 KB | None | 0 0
  1. x0=0;x1=0;x2=0;x3=0;x4=0
  2. b=300
  3. for x in range(1023):
  4.     if x//b == 0:
  5.         x0=x0+1
  6.     elif x//b == 1:
  7.         x1=x1+1
  8.     elif x//b == 2:
  9.         x2=x2+1
  10.     elif x//b == 3:
  11.         x3=x3+1
  12.     else:
  13.         x4=x4+1    
  14. print (x0,x1,x2,x3,x4)        
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