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Varvara_Golovnova

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Nov 6th, 2024
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  1. var
  2. a : array [1..20,1..20] of longint;
  3. j,i,sum1,sum2,sum3,sum4,sum5,n,m : longint;
  4. begin
  5. readln(n);
  6. readln(m);
  7. for i:=1 to n do
  8. for j:=1 to m do
  9. read(a[i,j]);
  10. sum1:=0;
  11. for i:=1 to n do
  12. for j:=1 to m do
  13. if a[i,j]=m then
  14. sum1:=sum1+1;
  15. writeln(sum1);
  16. for i:=1 to n do
  17. for j:=1 to m do
  18. read(a[i,j]);
  19. sum2:=0;
  20. for i:=1 to n do
  21. for j:=1 to m do
  22. if a[i,j]=m then
  23. sum2:=sum2+1;
  24. writeln(sum2);
  25. for i:=1 to n do
  26. for j:=1 to m do
  27. read(a[i,j]);
  28. sum3:=0;
  29. for i:=1 to n do
  30. for j:=1 to m do
  31. if a[i,j]=m then
  32. sum3:=sum3+1;
  33. writeln(sum3);
  34. for i:=1 to n do
  35. for j:=1 to m do
  36. read(a[i,j]);
  37. sum4:=0;
  38. for i:=1 to n do
  39. for j:=1 to m do
  40. if a[i,j]=m then
  41. sum4:=sum4+1;
  42. writeln(sum4);
  43. for i:=1 to n do
  44. for j:=1 to m do
  45. read(a[i,j]);
  46. sum5:=0;
  47. for i:=1 to n do
  48. for j:=1 to m do
  49. if a[i,j]=m then
  50. sum5:=sum5+1;
  51. writeln(sum5);
  52. end.
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