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- var
- a : array [1..20,1..20] of longint;
- j,i,sum1,sum2,sum3,sum4,sum5,n,m : longint;
- begin
- readln(n);
- readln(m);
- for i:=1 to n do
- for j:=1 to m do
- read(a[i,j]);
- sum1:=0;
- for i:=1 to n do
- for j:=1 to m do
- if a[i,j]=m then
- sum1:=sum1+1;
- writeln(sum1);
- for i:=1 to n do
- for j:=1 to m do
- read(a[i,j]);
- sum2:=0;
- for i:=1 to n do
- for j:=1 to m do
- if a[i,j]=m then
- sum2:=sum2+1;
- writeln(sum2);
- for i:=1 to n do
- for j:=1 to m do
- read(a[i,j]);
- sum3:=0;
- for i:=1 to n do
- for j:=1 to m do
- if a[i,j]=m then
- sum3:=sum3+1;
- writeln(sum3);
- for i:=1 to n do
- for j:=1 to m do
- read(a[i,j]);
- sum4:=0;
- for i:=1 to n do
- for j:=1 to m do
- if a[i,j]=m then
- sum4:=sum4+1;
- writeln(sum4);
- for i:=1 to n do
- for j:=1 to m do
- read(a[i,j]);
- sum5:=0;
- for i:=1 to n do
- for j:=1 to m do
- if a[i,j]=m then
- sum5:=sum5+1;
- writeln(sum5);
- end.
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