Java Armstrong Number Exercise

package armstrongnumbers;

import java.util.Objects;

final class IntegerHolder {

    private Integer x;

    public IntegerHolder() {
        this.x = 0;
    }

    public IntegerHolder(Integer x) {
        this.x = x;
    }

    public Integer getX() {
        return this.x;
    }

    public void setX(Integer x) {
        this.x = x;
    }
}

final class ArmstrongNumber {

    private IntegerHolder value;
    private Integer sum;

    public ArmstrongNumber(IntegerHolder value) {
        this.value = value;
    }

    public IntegerHolder getValue() {
        return value;
    }

    public Integer getSum() {
        return sum;
    }

    public void setValue(IntegerHolder value) {
        this.value = value;
    }

    public void findSum(final Integer base) {
        Integer tmp = this.value.getX(), tmp_sum = 0;
        do {
            tmp_sum += (int) Math.pow(tmp % base, 3);
            tmp /= base;
        } while (tmp != 0);
        this.sum = tmp_sum;
    }

    public Boolean isArmstrongNumber() {
        return Objects.equals(this.getValue().getX(), this.getSum());
    }

}

/**
 *
 * @author Aidan
 */
public class ArmstrongNumbers {

    private static final int LOOPS = 1000, BASES = 20;

    public static void main(String[] args) {
        IntegerHolder base = new IntegerHolder();
        for (Integer i = 2; i <= LOOPS; i++) {
            ArmstrongNumber tmp = new ArmstrongNumber(base);
            base.setX(i);
            for (Integer j = 2; j <= BASES; j++) {
                tmp.findSum(j);
                if (tmp.isArmstrongNumber()) {
                    System.out.println("In base " + j + ", " + i + " is an Armstrong number.");
                    System.out.flush();
                }
            }
            if (tmp.isArmstrongNumber()) {
                System.out.println();
                System.out.flush();
            }
        }
    }

}