LaTeX MWE refering to vertical line on algorithm package

\documentclass[final,5p,times,twocolumn,authoryear]{elsarticle}



\usepackage{algorithm}
\usepackage{algpseudocode}
\usepackage{etoolbox}
\usepackage{lipsum}

\usepackage{amsmath,amsfonts,amssymb,yfonts}
\usepackage{cleveref}



% Creating new commands...

\newcommand{\Test}{$\mathcal{D}_{i^{\ast}\xi\textfrak{N}^{i^{\ast}}}$}


% Patch to correct the way of vertical lines are align or arranged throughout the code using long texts in a line, becouse theses ones is broken due to long texts. This is solution provid by <https://tex.stackexchange.com/a/524700/155670>.

\makeatletter
% start with some helper code
% This is the vertical rule that is inserted
\newcommand*{\algrule}[1][\algorithmicindent]{%
    \hspace*{.2em}% <------------- This is where the rule starts from
    \vrule %height .75\baselineskip depth .25\baselineskip
    \hspace*{\dimexpr#1-.2em-.4pt}%
}

\newcommand{\StatePar}[1]{%
    \State\parbox[t]{\dimexpr\linewidth-\ALG@thistlm}{\strut #1\strut}%
    \vspace{-\lineskip}
}

\newcount\ALG@printindent@tempcnta
\def\ALG@printindent{%
    \ifnum \theALG@nested > 0% is there anything to print
    \ifx\ALG@text\ALG@x@notext% is this an end group without any text?
    % do nothing
    \else
    \unskip
    % draw a rule for each indent level
    \ALG@printindent@tempcnta=1
    \loop
    \algrule[\csname ALG@ind@\the\ALG@printindent@tempcnta\endcsname]%
    \advance \ALG@printindent@tempcnta 1
    \ifnum \ALG@printindent@tempcnta<\numexpr\theALG@nested+1\relax
    \repeat
    \fi
    \fi
}
% the following line injects our new indent handling code in place of the default spacing
\patchcmd{\ALG@doentity}{\noindent\hskip\ALG@tlm}{\ALG@printindent}{}{\errmessage{failed to patch}}
\patchcmd{\ALG@doentity}{\item[]\nointerlineskip}{}{}{} % no spurious vertical space
% end vertical rule patch for algorithmicx
\makeatother

% Add \struts to keywords
\algrenewcommand\algorithmicend{\strut\textbf{end}}
\algrenewcommand\algorithmicdo{\strut\textbf{do}}
\algrenewcommand\algorithmicwhile{\strut\textbf{while}}
\algrenewcommand\algorithmicfor{\strut\textbf{for}}
\algrenewcommand\algorithmicforall{\strut\textbf{for all}}
\algrenewcommand\algorithmicloop{\strut\textbf{loop}}
\algrenewcommand\algorithmicrepeat{\strut\textbf{repeat}}
\algrenewcommand\algorithmicuntil{\strut\textbf{until}}
\algrenewcommand\algorithmicprocedure{\strut\textbf{procedure}}
\algrenewcommand\algorithmicfunction{\strut\textbf{function}}
\algrenewcommand\algorithmicif{\strut\textbf{if}}
\algrenewcommand\algorithmicthen{\strut\textbf{then}}
\algrenewcommand\algorithmicelse{\strut\textbf{else}}

\algrenewcommand\algorithmicrequire{\strut\textbf{Input:}}
\algrenewcommand\algorithmicensure{\strut\textbf{Output:}}

\let\oldState\State
\renewcommand{\State}{\oldState\strut}



\begin{document}


\begin{align}
    a & = b \label{eq:1}
\end{align}

% ---> Algorithm 01.
\begin{algorithm}
    \caption{Arbitrary Algorithm}
    \begin{algorithmic}[1]
        \Require A matrix $\mathbf{A}$ of size $m\times n$.
        \Ensure Something.
        \Procedure{MainProcedure}{}
            \State $a\gets{}b$
            \For{$i$ in $m$}
                \For{$j$ in $n$}
                \showoutput
                    \If{$i = j$}
                        \State Obtain \Test
                        \State $\textfrak{M}^{(l)}$
                        \State $\textfrak{M}^{(l)}$
                        \State $\displaystyle{\sum_{i=1}^{c}{\alpha^{(b^{\ast})}}}$
                        \State According to \cref{eq:1}
                        \State According to \cref{eq:1}
                        \State According to \cref{eq:1}
                        \State $\beta = \displaystyle{\max_{i=1}^{c}\!\left(\alpha^{(\beta^{\ast})}\right)}$
                        \StatePar{Select a random action. \lipsum[1]}
                    \Else
                        \If{$i = j + 1$}
                            \State Stay silent
                        \Else
                            \State Break
        \algstore{bkbreak}
    \end{algorithmic}
\end{algorithm}

% ---> Algorithm 01: continuation.
\begin{algorithm}
    \begin{algorithmic}
        \algrestore{bkbreak}
                        \EndIf
                    \EndIf
                \EndFor
            \EndFor
            \ForAll{condition}
            \EndFor
        \EndProcedure
    \end{algorithmic}
\end{algorithm}


\end{document}