"""
Given a list of N numbers, write a function to shift the numbers circularly by some integer k (where k < N).
The function should take a list and k as a arguments and return the shifted list.
"""
RIGHT = 1
LEFT = 0


def main():
    print("THe shifter function. Shits all elements in a array given a shift point and a direction")
    print("Populate the array!")
    print()

    numbers_list = []
    while True:
        number = int(input("Give a number: "))
        numbers_list.append(number)
        another = input("Another? ['y'/'n']: ")
        if another.lower() == 'n':
            break

    print("The array is: ", numbers_list)

    direction = input("Give the direction to switch the numbers: ")
    if direction.lower() == 'right':
        direction = RIGHT
    elif direction.lower() == 'left':
        direction = LEFT

    shifter_int = int(input("The shifter element: "))

    print(shifter(numbers_list, shifter_int, direction))


def shifter(numbers, shift_integer, shift_direction):
    """

    :param numbers: it is the list of numbers generated by the user in the main function
    :param shift_integer: the integer to shift from - the index to be hold on place
    :param shift_direction: the direction to shift the number
    :return: the shifter list
    """

    # the complicate way - shifting to the right without list slicing
    # using a while loop and a container to hold the data - remove it and then append it at the end of the list
    # one could use slicing - easies way
    if shift_direction:
        while shift_integer >= 0:
            holder = numbers[shift_integer-1]
            numbers.remove(holder)
            numbers.append(holder)
            shift_integer -= 1

        return numbers

    # the easiest way - using the integer as a cut element and split the initial list accordingly
    else:
        numbers = numbers[shift_integer:][::-1] + numbers[:shift_integer]
        return numbers


if __name__ == '__main__':
    main()