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Jan 12th, 2018
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  1. 1
  2.  
  3. scanf("%d %d %d", &a,&b,&c);
  4. printf("%f",((a+b+c)/3));
  5.  
  6. 2
  7.  
  8. scanf("%d", &a);
  9.  
  10. if((a>0) && ((a%2)==0)){
  11. printf("par positivo");
  12. }elseif((a<0) && ((a%2)==0)) {
  13. printf("par negativo");
  14. }elseif((a>0) && ((a%2)==1)) {
  15. printf("impar positivo");
  16. }elseif((a<0) && ((a%2)==1)) {
  17. printf("par negativo");
  18. }else{
  19. printf("nulo");
  20. }
  21.  
  22. 3
  23. a = 1;
  24. c=0;
  25. while(a>0){
  26.  
  27. scanf("%d",&a);
  28. if(a>0){
  29. b+=a;
  30. c++;
  31. }
  32. }
  33. printf("%f",(b/c));
  34.  
  35. 4
  36.  
  37. scanf("%f",&a));
  38. b=0;
  39. while(b<a){
  40. c += b;
  41. b += 2;
  42. }
  43. printf("%d",c);
  44.  
  45. 5
  46.  
  47. for(int b =0;b<10;b++){
  48. scanf("%f",&a));
  49. if ((a>10)&&(a<20)) c++;
  50. }
  51.  
  52. printf("%d",c);
  53.  
  54. 6
  55.  
  56. scanf("%f",&a));
  57. scanf("%f",&b));
  58. switch (a){
  59. case 3: printf("%f",(b*b*(1.73/4))); break
  60. case 4: printf("%f",(b*b)); break
  61. case 6: printf("%f",(6*b*b*(1.73/4))); break
  62. default: printf("nao sei calcular");
  63. }
  64.  
  65. 7
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