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Taraxacum

Polynomial's Value

Nov 15th, 2018
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C++ 0.81 KB | None | 0 0
  1. #include <iostream>
  2.  
  3. using namespace std;
  4.  
  5. int polynomial1(int* coff, int n, int x)
  6. {
  7.     int xsq = 1;
  8.     int val = 0;
  9.  
  10.     for (int ord = 0; ord <= n; ord++) {
  11.         val += xsq * coff[ord];
  12.         xsq *= x;
  13.     }
  14.  
  15.     return val;
  16. }
  17.  
  18. int polunomial2(int* coff, int n, int x)
  19. {
  20.     int val = coff[n];
  21.  
  22.     for (int i = n - 1; i >= 0; i--) {
  23.         val = val * x + coff[i];
  24.     }
  25.  
  26.     return val;
  27. }
  28.  
  29. int main()
  30. {
  31.     int coff1[] = { 1, 2, 1 };
  32.     int n = 2;
  33.  
  34.     cout << polynomial1(coff1, n, 1) << " " << polynomial1(coff1, n, 2) << endl;
  35.  
  36.     int coff2[] = { 1, 2 };
  37.     n = 1;
  38.     cout << polynomial1(coff2, n, 1) << " " << polynomial1(coff2, n, 2) << endl;
  39.  
  40.     int coff3[] = { 2 };
  41.     n = 0;
  42.     cout << polynomial1(coff3, n, 1) << " " << polynomial1(coff3, n, 2) << endl;
  43. }
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