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Jun 28th, 2017
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  1. (: Method 3: return items from $seq1 that do not exist in $seq2 :)
  2. (: most elegant in my opinion :)
  3.  
  4. let $seq1 := (<el id="a"/>,<el id="2"/>,<el id="3"/>,<el id="4"/>,<el id="5"/>)
  5. let $seq2 := (<el id="a"/>,<el id="b"/>,<el id="c"/>,<el id="d"/>,<el id="1"/>)
  6. let $s2ids := distinct-values($seq2/@id)
  7. return
  8. $seq1[not(@id=$s2ids)]
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