Super Sitrus Optimization Thoughts

Super Sitrus (FIWAM) Berries
-Activates when current HP <= floor(Pokemon's HP / 4)

-Impossible to make an attack a guaranteed 2HKO with super Sitrus; to activate, the initial hit must deal 75% (100-75 = 25); after recovering 50%, it is in KO range of the second 75% damage. It is possible to make the attack a 2HKO a certain % of the time, however, if the original attack has any damage rolls less than 75%, but also has damage rolls greater than 75%. For example, assume a Pokemon's attack deals 65% - 75% damage, with the max damage roll triggering super Sitrus but no other damage rolls trigger it. There would therefore be a 1/16 chance to hit that max damage roll on the first hit, and a 15/16 chance to hit the other non-KOing damage rolls on the second hit. That should be a 15/256 chance to survive the attack. I would imagine the maximum chance to make an attack a 3HKO with super Sitrus Berry should never be higher than 25%.

Ansel has proof of this

Example
Suppose given Pokemon with HP stats 100, 101, 102, and 103 (labeled A, B, C, D respectively)

Pokemon A - 100 HP
Requires 75 damage to activate super Sitrus
100-75 = 25; 25+50 = 75; 75-75 = 0

Pokemon B - 101 HP
Requires 76 damage to activate super Sitrus
101-76 = 25; 25+50 = 75; 75-76 = -1

Pokemon C and D involve similar cases to B

Suppose set of damage rolls (69, 70, 71, 71, 72, 73, 73, 74, 75, 77, 78, 79, 79, 80, 81, 83)

Pokemon A - 100 HP
Requires 75 damage to activate super Sitrus
rolls[8] - rolls[15] satisfy super Sitrus activation condition (8/16)
After rolls[8]:  100 - 75 = 25; 25+50 = 75 (8/16 to survive)
After rolls[9]:  100 - 77 = 23; 23+50 = 73 (5/16 to survive)
After rolls[10]: 100 - 78 = 22; 22+50 = 72 (5/16 to survive)
After rolls[11]: 100 - 79 = 21; 21+50 = 71 (2/16 to survive)
After rolls[12]: 100 - 79 = 21; 21+50 = 71 (2/16 to survive)
After rolls[13]: 100 - 80 = 20; 20+50 = 70 (1/16 to survive)
After rolls[14]: 100 - 81 = 19; 19+50 = 69 (0/16 to survive)
After rolls[15]: 100 - 83 = 17; 17+50 = 67 (0/16 to survive)

rolls[14] and rolls[15] cannot survive second attack, so they are to be excluded
rolls[8] - rolls[13] are possible

1/256(8+5+5+2+2+1) = 23/256, ~8.98%