eratho_sieve

def eratho(n):
    result = []
    printer = []
    for i in range(n+1):
        result.append(True)
    for j in range(n+1):
        if j <= 1:
            result[j] = False
        else:
            for i in range(2, n+1):
                if j % i == 0 and j != i:
                    result[j] = False
    for i in range(len(result)):
        if result[i]:
            printer.append(i)
    return(printer)