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Mar 21st, 2019
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  1. $ ls
  2. archive testfolder
  3. $ ls archive/
  4. $ ls testfolder/
  5. tesfile1 tesfile2 tesfile3
  6.  
  7. for i in $(ls testfolder/); do 7za a archive/$i testfolder/$i; done
  8.  
  9. $ ls archive/
  10. tesfile1.7z tesfile2.7z tesfile3.7z
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