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lessientelrunya

ajaxrequest

Jul 25th, 2017
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  1. function ajax_request(argument)
  2. {
  3.     var aj = new XMLHttpRequest();
  4.     aj.onreadystatechange = function() {
  5.         if aj.readyState == 4 && aj.status == 200)
  6.             // do something to the page
  7.     };
  8.  
  9.     aj.open("GET", /* url */, true);
  10.     aj.send();
  11. }
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