# Note: This is syntatically valid ruby code, but it
# does not work because ruby has a bounded callstack

myFunc = lambda do |n|
  lambda do |f|
    if (n == 0) then
      f
    else
      q = myFunc.call(n-1)
      r = ( q.call(q.call(f)) ).call("a")

      fa = q
      for i in 0..r.length**2
        fa = lambda do |func|
          q.call(fa.call(func))
        end
      end

      fa.call(f)
    end
  end
end

double = lambda do |str|
  str + str
end

puts (myFunc.call(65502).call(double).call("9"))