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Pagoniusz

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May 10th, 2015
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C++ 0.26 KB | None | 0 0
  1. double sum=0;
  2.         for (int j = 0; j < n; j++)
  3.         {
  4.             sum += powf((function_values[j].y - aprox_values[j].y),2);
  5.                 //function_values[j].y = wynik prawidlowy; aprox_values[j].y = aproksymowany
  6.         }
  7.         sum = abs(sum);
  8.         cout << "Blad aproksymacji = " << sum << endl;
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