Advertisement
Not a member of Pastebin yet?
Sign Up,
it unlocks many cool features!
- {
- "cells": [
- {
- "cell_type": "code",
- "execution_count": 1,
- "metadata": {
- "collapsed": true
- },
- "outputs": [],
- "source": [
- "import astropy as ay\n",
- "import numpy as np\n",
- "import matplotlib as mpl\n",
- "import matplotlib.pyplot as plt\n",
- "from astropy.io import ascii\n",
- "\n",
- "mpl.rcParams['figure.figsize'] = (10, 6)\n",
- "mpl.rcParams['font.size'] = 14\n",
- "import urllib.request"
- ]
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "# Astronomy 5830, HW 2\n",
- "\n",
- "## Lyra Cao\n",
- "\n",
- "### Problem 1:\n",
- "\n",
- "Signal-to-noise: An interesting object has been discovered with $r_{AB} = 22$ mag and you would\n",
- "like to observe it further. Note that the SDSS r-band has $\\lambda _c= 0.626 \\mu m$, $d \\lambda = 0.1064 \\mu m$, and the\n",
- "zeropoint of the AB magnitude system is $3631 Jy$.\n",
- "\n",
- "\n",
- "#### 1a. What is the flux zeropoint per unit wavelength $f _{\\lambda}$? Please use $[erg] [s^{-1}] [cm^{-2}] [A^{-1}]$"
- ]
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "#### Answer, 1a:\n",
- "\n",
- "\\begin{equation}\n",
- "f _{\\nu} = 3631 [Jy] = 3.631 \\times 10^3 \\times 10^{−23} [erg] [s^{−1}] [Hz^{−1}] [cm^{−2}] = 3.631 \\times 10^{−20} [erg] [s^{−1}] [Hz^{−1}] [cm^{−2}]\n",
- "\\end{equation}\n",
- "\n",
- "By the chain rule,\n",
- "\n",
- "\\begin{equation}\n",
- "\\frac{\\partial F}{\\partial \\lambda} = \\frac{\\partial F}{\\partial \\nu} \\frac{\\partial \\nu}{\\partial \\lambda}\n",
- "\\end{equation}\n",
- "\n",
- "So, since $f _{\\nu} \\equiv \\frac{\\partial F}{\\partial \\nu}$ and $f _{\\lambda} \\equiv \\frac{\\partial F}{\\partial \\lambda}$,\n",
- "\n",
- "\\begin{equation}\n",
- "f_{\\lambda} = f_{\\nu} \\left| \\frac{\\partial \\nu}{\\partial \\lambda} \\right|\n",
- "\\end{equation}\n",
- "\n",
- "\\begin{equation}\n",
- "c = \\lambda \\nu\n",
- "\\end{equation}\n",
- "\n",
- "So,\n",
- "\n",
- "\\begin{equation}\n",
- "\\nu = \\frac{c}{\\lambda}\n",
- "\\end{equation}\n",
- "\n",
- "\\begin{equation}\n",
- "\\frac{\\partial \\nu}{\\partial \\lambda} = -\\frac{c}{\\lambda ^2}\n",
- "\\end{equation}\n",
- "\n",
- "So,\n",
- "\n",
- "\\begin{equation}\n",
- "f_{\\lambda} = f_{\\nu} \\frac{c}{\\lambda ^2}\n",
- "\\end{equation}\n",
- "\n",
- "With our existing values for $f _{\\nu}$ in cgs units, we multiply by $c=2.99792458 \\times 10^{10}$, and divide by $\\lambda$ in Angstroms ($6260 A$) and $\\lambda$ in cm ($6.26 \\times 10^{-4} cm$).\n",
- "\n",
- "So,\n",
- "\n",
- "\\begin{equation}\n",
- "f_{\\lambda} = 3.631 \\times 10^{−20} [erg] [s^{−1}] [Hz^{−1}] [cm^{−2}] * 2.99792458 \\times 10^{10} [cm] [s^{-1}] * 1/6260 [A^{-1}] * 1/(6.26 \\times 10^{-4}) [cm^{-1}]\n",
- "\\end{equation}\n",
- "\n",
- "\\begin{equation}\n",
- "f_{\\lambda} \\approx 2.778 \\times 10^{-10} [erg] [s^{−1}] [cm^{−2}] [A^{-1}]\n",
- "\\end{equation}\n",
- "\n",
- "The flux zeropoint is $f_{\\lambda} \\approx 2.778 \\times 10^{-10} [erg] [s^{−1}] [cm^{−2}] [A^{-1}]$."
- ]
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "#### 1b. What is the zeropoint in [$\\gamma$][$s^{-1}$][$cm^{-2}$][$A^{-1}$]?"
- ]
- },
- {
- "cell_type": "code",
- "execution_count": null,
- "metadata": {
- "collapsed": true
- },
- "outputs": [],
- "source": []
- }
- ],
- "metadata": {
- "kernelspec": {
- "display_name": "Python 3",
- "language": "python",
- "name": "python3"
- },
- "language_info": {
- "codemirror_mode": {
- "name": "ipython",
- "version": 3
- },
- "file_extension": ".py",
- "mimetype": "text/x-python",
- "name": "python",
- "nbconvert_exporter": "python",
- "pygments_lexer": "ipython3",
- "version": "3.5.3"
- }
- },
- "nbformat": 4,
- "nbformat_minor": 0
- }
Advertisement
Add Comment
Please, Sign In to add comment
Advertisement