FizzBuzz problem JavaScript

// FizzBuzz Practice by Saidur Rahman Setu (@srsetu)

var output= [];
var count = 1;

function FizzBuzz() {
    while (count <= 50) {
    // if statement for 3 and 5
    if ((count % 3) === 0 && (count % 5) === 0) {
        output.push("FizzBuzz");
    } else if ((count % 5) === 0) {
        output.push("Buzz");
    } else if ((count % 3) === 0) {
        output.push("Fizz");
    } else {
        output.push(count);
    };

    // Increment
    count++;
    }

    return output;
};

var popUp = FizzBuzz();

alert(popUp);