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- $ python -m timeit "ls=list(range(1000))" "b=ls[:];b.clear()"
- 10000 loops, best of 5: 21.6 usec per loop
- $ python -m timeit "ls=list(range(1000))" "b=ls[:];del b[:]"
- 10000 loops, best of 5: 21.8 usec per loop
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