{
 "cells": [
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": [
    "import numpy as np"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# 1. numpy로 5x5 랜덤 행렬 만들기"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 4,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[[0.27256445 0.98917995 0.07114072 0.79926405 0.23969014]\n",
      " [0.80478659 0.09748369 0.7503959  0.03095843 0.05164492]\n",
      " [0.13663289 0.14028369 0.78751947 0.72739145 0.79974777]\n",
      " [0.40468762 0.22329369 0.75673081 0.29983754 0.81019219]\n",
      " [0.9097251  0.24756749 0.27425579 0.98508658 0.37157529]]\n"
     ]
    }
   ],
   "source": [
    "a=np.random.random((5,5))\n",
    "print(a)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# 2.1 1에서 만든 행렬 각 행의 최대값 구하기"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 5,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "array([0.98917995, 0.80478659, 0.79974777, 0.81019219, 0.98508658])"
      ]
     },
     "execution_count": 5,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "a.max(1)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# 2.2 1에서 만든 행렬 각 열의 최대값 구하기"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 6,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "array([0.9097251 , 0.98917995, 0.78751947, 0.98508658, 0.81019219])"
      ]
     },
     "execution_count": 6,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "a.max(0)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# 2.3 1에서 만든 행렬 전체의 최대값 구하기"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 7,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "0.9891799457333734"
      ]
     },
     "execution_count": 7,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "a.max()"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# 3. 5x5 에서 가운데 3x3 구하기"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 8,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[[0.09748369 0.7503959  0.03095843]\n",
      " [0.14028369 0.78751947 0.72739145]\n",
      " [0.22329369 0.75673081 0.29983754]]\n"
     ]
    }
   ],
   "source": [
    "b=a[1:4,1:4]\n",
    "print(b)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# 4.1 1에서 만든 5x5 행렬을 1차원 벡터로 만들기"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 12,
   "metadata": {
    "scrolled": true
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[0.27256445 0.98917995 0.07114072 0.79926405 0.23969014 0.80478659\n",
      " 0.09748369 0.7503959  0.03095843 0.05164492 0.13663289 0.14028369\n",
      " 0.78751947 0.72739145 0.79974777 0.40468762 0.22329369 0.75673081\n",
      " 0.29983754 0.81019219 0.9097251  0.24756749 0.27425579 0.98508658\n",
      " 0.37157529]\n"
     ]
    }
   ],
   "source": [
    "b = a.flatten()\n",
    "print(b)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# 4.2 1에서 만든 5x5 행렬을 1x25 행렬로 만들기"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 13,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "array([[0.27256445, 0.98917995, 0.07114072, 0.79926405, 0.23969014,\n",
       "        0.80478659, 0.09748369, 0.7503959 , 0.03095843, 0.05164492,\n",
       "        0.13663289, 0.14028369, 0.78751947, 0.72739145, 0.79974777,\n",
       "        0.40468762, 0.22329369, 0.75673081, 0.29983754, 0.81019219,\n",
       "        0.9097251 , 0.24756749, 0.27425579, 0.98508658, 0.37157529]])"
      ]
     },
     "execution_count": 13,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "a.reshape(1,25)"
   ]
  }
 ],
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