How to convert mysql data base table data in json using php
<?php
$host = "emriphone.db.6420177.hostedresource.com";
$user = "emriphone";
$pass = "Light12-";
$database = "emriphone";

$linkID = mysql_connect($host, $user, $pass) or die("Could not connect to host.");
mysql_select_db($database, $linkID) or die("Could not find database.");

$sth = mysql_query("SELECT * FROM ProviderAppointmentListings");
$rows = array();
while($r = mysql_fetch_assoc($sth)) {
   $rows[] = $r;
}
print json_encode($rows);
?>

$query = mysql_query("SELECT * FROM table");
$rows = array();
while($row = mysql_fetch_assoc($query)) {
    $rows[] = $row;
}
print json_encode($rows);

if (!function_exists('json_encode'))
{
  function json_encode($a=false)
  {
    if (is_null($a)) return 'null';
    if ($a === false) return 'false';
    if ($a === true) return 'true';
    if (is_scalar($a))
    {
      if (is_float($a))
      {
        // Always use "." for floats.
        return floatval(str_replace(",", ".", strval($a)));
      }

      if (is_string($a))
      {
        static $jsonReplaces = array(array("\", "/", "n", "t", "r", "b", "f", '"'), array('\\', '\/', '\n', '\t', '\r', '\b', '\f', '"'));
        return '"' . str_replace($jsonReplaces[0], $jsonReplaces[1], $a) . '"';
      }
      else
        return $a;
    }
    $isList = true;
    for ($i = 0, reset($a); $i < count($a); $i++, next($a))
    {
      if (key($a) !== $i)
      {
        $isList = false;
        break;
      }
    }
    $result = array();
    if ($isList)
    {
      foreach ($a as $v) $result[] = json_encode($v);
      return '[' . join(',', $result) . ']';
    }
    else
    {
      foreach ($a as $k => $v) $result[] = json_encode($k).':'.json_encode($v);
      return '{' . join(',', $result) . '}';
    }
  }
}

$sql="Select * from table";
$l= array();
$result = mysql_query($sql);
while ($row = mysql_fetch_assoc($result)) {
  $l[] = $row;
}
$j = json_encode($l);
echo $j;