Sorting 3 integers

import java.util.Scanner;
public class Chapter3_8Sorting3Integers {

    public static void main(String[] args) {
        Scanner kb = new Scanner(System.in);

        // prompt the user for 3 integers
        System.out.println("Enter 3 integers");

        // retrieve the integers from the console
        int num1 = kb.nextInt();
        int num2 = kb.nextInt();
        int num3 = kb.nextInt();

        System.out.println("the numbers pre-sorted are " + num1 + " "+ num2+ " "+num3);

        // Test the integers.  If they are in the wrong order you must use a swap.  We DO NOT use else if here because
        if (num1 >num2){                                //  we need every case to be tested
            int temp = num1;    // now num1 is stored in the temp variable
            num1 = num2;        // now num1 gets num2.  At this moment they are the same value.
            num2 = temp;        // now  num2 gets the value stored in temp (which was the original num1)
        }
        if (num2 >num3){
            int temp = num2;
            num2 = num3;
            num3 = temp;
        }
        if (num1 >num2){
            int temp = num1;
            num1 = num2;
            num2 = temp;
        }
        System.out.println("The numbers sorted are "+ num1 + " "+ num2+ " "+num3);


    }

}