Array with 6

Array with 6
Given an array of ints, compute recursively if the array contains a 6.

We'll use the convention of considering only the part of the array that begins at the given index. In this way, a recursive call can pass index+1 to move down the array. The initial call will pass in index as 0.

Input
On the first line you will be given the comma separated array. On the second line you will receive the index.

Output
On the only output line you should print the result.

Sample tests
Input
1,6,4
0
Output
true
Input
1,4
0
Output
false

import java.util.Scanner;

public class ArrayWith6 {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        String[] input = scanner.nextLine().split(",");
        int index = Integer.parseInt(scanner.nextLine());
        System.out.println(containsSix(input, index));
    }

    static boolean containsSix(String[] input, int index){
        if( index < 0 || index > input.length-1){ // index is out of bounds or not found
            return false;
        } else if(input[index].equals("6")){
            return true; // If we see it, return true.
        }
        return containsSix(input ,index + 1);
        }

    }