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Jul 22nd, 2017
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  1. SELECT worker.last_name AS "Tyontekija", employee_id AS "Tt#", manager.last_name AS "Manageri",
  2. manager_id AS "Mgr#"
  3. FROM employees worker JOIN employees manager
  4. ON (worker.manager_id = manager.employee_id)
  5. ORDER BY 'Tt#' ASC, 'Mgr#' ASC;
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