/**
 * Write a script that will find all the vowels [a,e,i,o,u] inside any string
 * and then flip the order of only the vowels. If there is an odd number of vowels
 * then the one in the middle stays in the same position. Complete this task with the
 * fewest number of loops and iterations as possible.
 * Eg:
 * cottage => cettago
 * hello => holle
 * sauce => seuca
 * javascript => jivascrapt
 */
let log = console.log;

let process = word => {
  let matches = Array.from(word).reduce((acc, curr, idx) => {
    if (["a", "e", "i", "o", "u"].includes(curr)) {
      acc.push(idx);
    }
    return acc;
  }, []);
  log(matches); //positions of the vowels
  let len = matches.length;
  let wordCopy = Array.from(word);
  for (let i = 1; i <= len / 2; i++) {
    let ltr = word.substring(matches[len - i], matches[len - i] + 1);
    let removed = wordCopy.splice(matches[i - 1], 1, ltr);
    wordCopy.splice(matches[len - 1], 1, removed[0]);
    word = wordCopy.join("");
  }
  return word;
};

log(process("javascript"));
log(process("hello"));