random numbers m-programmer English

random numbers m-programmer English

easy way:((you don’t need anything, but, there is no way to prevent cheating):

method_A_: just choose a number from 0 to 9

method_B_:  just choose a number from 0 to 127

method_C_: just choose a number from 0 to 100

method_D_: just choose a number from 1 to 10

method_E_: just choose a number from 1 to 100

write your result down on the variables paper L=result



difficult ways:

method_A_: from 0 to 9  (needs dice and coins)

method_B_: from 0 to 127  (binary version, only needs coins)


method_C_: from 0 to 100  (binary version1, the probability of 0 to 27 to come out will decrease, only needs coins)
choose whichever you want between the following two;
from 0 to 100  (binary version1, the probability of 0 to 27 to come out will decrease, only needs coins)
or
from 0 to 100  (binary version2(may take many tries),only needs coins)

method_D_: from 1 to 10  (decimal version1, needs dice and coins)

method_E_:
choose whichever you want between the following two;
from 1 to 100  (decimal version1, needs dice and coins)
or
from 1 to 100  (decimal version2, (6,8,9 and so on won’t come out, needs dice, the executor cannot cheat))

write your result down on the variables paper L=result


from 1 to 10  (decimal version1, needs dice and coins)

roll the dice, if 6 comes out do it again.
then, toss a coin, if it comes out tails then add 5 to the result



from 0 to 9  (needs dice and coins)

from 1 to 10-1


from 1 to 100  (decimal version1, needs dice and coins)

the result of from 0 to 9 X 1 plus

the result of from 0 to 9 X 10 plus

the result of from 0 to 9 X 100 plus



from 0 to 127  (binary version, only needs coins)

start with 0

put 7 coins in a cup, then shaking the cup a lot, then drop them on the table, then lay them down in a line from left to right

if coin #1 is heads, add 1

if coin #2 is heads, add 2

if coin #3 is heads, add 3

if coin #4 is heads, add 8

if coin #5 is heads, add 16

if coin #6 is heads, add 32

if coin #7 is heads, add 64



from 0 to 100  (binary version1, the probability of 0 to 27 to come out will decrease, only needs coins)

do from 0 to 127 and then if the result is more then 100 subtract 100



from 0 to 100  (binary version2(may take many tries))

do from 0 to 127 and then if the result is more then 100 repeat it.





from 1 to 100  (decimal version2, (6,8,9and so on won’t come out, needs dice, the executor cannot cheat))

you need 2 players to play this game, the “player” and the “executor”
the executor does everything except where it is mentioned that the player should do something.

how to get a number from 0 to 50
Random_Number_0_to_50:
repeat until the result is not negative:
-roll first dice multiply times 10 then add the second roll of dice
-subtract 11
-the player should write down the results of both dice rolls and save them for later
-the executor should write down the hidden random number  and keep it hidden until the game is over
-be sure to record every pair of rolls of the dice and every hidden number for later verification

how to get a number 0 to 100
RandomNumberA is Random_Number_0_to_50
RandomNumberB is Random_Number_0_to_50
if RandomNumberB is 0 then change RandomNumberB to 1
make Random_number_Zero_to_100 into  RandomNumberA+RandomNumberB
write down L=Random_number_Zero_to_100 on the variables paper

after the game ends:
repeat for every pair of rolls of the dice:
repeat until the result is not negative:
-first roll of dice written down by player multiply times 10 then add the second roll of dice
-subtract 11
if the number is equal to the hidden random number then the executor did not cheat, otherwise he cheated