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- \documentclass[english]{article}
- \usepackage[T1]{fontenc}
- \usepackage[cp1250]{inputenc}
- \usepackage{amsmath}
- \usepackage{babel}
- \usepackage{polski}
- \begin{document}
- \author {IS Rok 2 Grupa 4\\Nr indeksu: 299765\\Nr na liście: 105}
- \title{Gabriela Śreniawska}
- \maketitle
- \section*{Lista 6 Zadanie 19
- \section*{Lista 7 Zadanie 22}
- \section*{Lista 8 Zadanie 11}
- \section*{Lista 9 Zadanie 36}
- \begin{center}
- $t^{2}y''+ty'+y=8t^{3}$
- $t^{2}y''+ty'+y=0$
- \end{center}
- }
- Podstawiamy:
- \begin{center}
- $y(t)=t^{k}$
- $y'(t)=kt^{k-1}$
- $y''(t)=k(k-1)t^{k-2}$
- $k(k-1)t^{k}+kt^{k}+t^{k}=0$
- \end{center}
- Wyliczamy Pierwiastki rlwnania:
- \begin{center}
- $k_{1}=-i$
- $k_{2}=i$
- \end{center}
- Podstawiamy i wyliczamy:
- \begin{center}
- $e^{\varTheta}=cos\varTheta+sin\Theta,$
- $t=e^{lnt}$
- $y_{1}(t)=cos(lnt)-isin(lnt)$
- $y_{2}(t)=cos(lnt)+isin(lnt)$
- $Y_{1}(t)=\frac{1}{2}y_{1}(t)+\frac{1}{2}y_{2}(t)=cos(lnt)$
- $Y_{2}(t)=sin(lnt)$
- \end{center}
- Otrzymujemy:
- \begin{center}
- $y(t)=c_{1}cos(lnt)+c_{2}sin(lnt)$
- \end{center}
- \section*{Lista 10 Zadanie 6}
- \section*{Lista 11 Zadanie 15}
- \end{document}
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