CONVERSOR DE BASES NUMÉRICAS BIN HEX OCT Python

#!/usr/bin/env python
# -*- coding: utf-8 -*-
#
#  ConversorOctaHexaBin.py
#
#  Copyright 2021 Elizeu Barbosa Abreu <[email protected]>
#
#  This program is free software; you can redistribute it and/or modify
#  it under the terms of the GNU General Public License as published by
#  the Free Software Foundation; either version 2 of the License, or
#  (at your option) any later version.
#
#  This program is distributed in the hope that it will be useful,
#  but WITHOUT ANY WARRANTY; without even the implied warranty of
#  MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
#  GNU General Public License for more details.
#
#  You should have received a copy of the GNU General Public License
#  along with this program; if not, write to the Free Software
#  Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston,
#  MA 02110-1301, USA.
#
#
from time import sleep
import os

def cls():
    os.system('clear')

def titulo():
    print('{:^45}\n'.format('CONVERSOR DE BASES NUMÉRICAS'))

def conversor():
    cls()
    titulo()

    print('''ESCOLHA UMA BASE PARA QUAL DESEJA CONVERTER:
    [1] PARA OCTA;
    [2] PARA HEXADECIMAL
    [3] PARA BINÁRIO
    [Ctrl+C] PARA SAIR
    ''')
    escolha = int(input('QUAL É A SUA ESCOLHA? '))

    if escolha == 1:
        e = 'OCTAL'
    elif escolha == 2:
        e = 'HEXADECIMAL'
    elif escolha == 3:
        e = 'BINÁRIO'
    else:
        print('Escolha inválida!!!')
        print('REINICIANDO APP....')
        sleep(3)
        conversor()

    num = int(input('QUE VALOR VOCÊ QUER CONVERTER PARA {}?: '.format(e)))

    print('-=' * 20)
    if escolha == 1:
        print('{} em OCTAL é {}...'.format(num, oct(num)[2:]))
    elif escolha == 2:
        print('{} em HEXADECIMAL é {}...'.format(num, hex(num)[2:]))
    elif escolha == 3:
        print('{} em BINÁRIO é {}...'.format(num, bin(num)[2:]))


    print('-=' * 20)
    sleep(7)
c = True
while c:
    conversor()