Angry Birds with laser beam (easy version)

#include<stdio.h>
//the code is small, its the comments that are making it look bigger, the comments are for better understanding
//using struct for easy passing to functions and easy calculations
struct point{
    // taking long long, because their multiplication may overload in int
    long long int x,y;
};



// To find orientation of ordered triplet (s, e, r).
// The function returns following values
// 0 --> s, e and r are collinear
// 1 --> Clockwise side
// 2 --> Counterclockwise side
int cross_product_sign(point s, point e, point r)
{
    //this formula is for cross product of three points
    long long int val = (e.y - s.y) * (r.x - e.x) -
              (e.x - s.x) * (r.y - e.y);

    // since we are only concerned with the sign, we are not returning the values

    if (val == 0) return 0;  // collinear
    //though for this problem, they will never be colinear, but we will need this concept for next problem

    return (val > 0)? 1: 2; // clock or counterclock wise
}

int main() {
    int t,n;
    point pig, bird, s, e;

    scanf("%d",&t);
    while(t--){
        scanf("%lld %lld %lld %lld",&s.x,&s.y,&e.x,&e.y);
        scanf("%lld %lld",&pig.x,&pig.y);
        scanf("%lld %lld",&bird.x,&bird.y);
        //you have to pass them in same order for both function calls
        int o1 = cross_product_sign(s,e,pig);
        int o2 = cross_product_sign(s,e,bird);

        if(o1!=o2){
            //there sign is not same
            //so on different side
            printf("Lose\n");
        }
        else{
            printf("Win\n");
        }
    }
    return 0;
}