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Dec 11th, 2017
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  1. . There are 6 cases of three digit palindromes: abcba, abccba, ababa, aaaaa, aaaaaa, bbbaaa
  2. . where a,b,c are digits and 9 > a,b,c > 0
  3. . Expanding this to polyatomic forms, we have:
  4. 1) x = abcba = 10001a + 1010b + 100c
  5. 2) x = abccba = 100001a + 10010b + 1100c
  6. 3) x = bbbaaa = 111000b + 111a
  7. 4) x = ababa = 10101a + 1010b
  8. 5) x = aaaaa = 11111a
  9. 6) x = aaaaaa 111111a
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