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1) Why is the school printing multiple times?

As you already know, the data returned by yelp.get_all_businesses() is a list of businesses, represented as a list of dictionaries. You're using the "schools" field of this dictionary (line 17) to get the schools associated with a business. However, a crucial thing to understand is that the abstraction associated with a businesses "schools" is the list of schools (coded as a list of strings), not a single school. For example, if you look at the 8th business ("Unique Pizza"), it has two schools that are associated with it!

>>> all_businesses[7]['name']
"Unique Pizza"
>>> all_businesses[7]['schools']
['Massachusetts Institute of Technology', 'Harvard University']

Originally, you appended each business['schools'] to the schoollist variable. This means that you end up with a list of lists of schools (most of which are only one school, but in the case of "Unique Pizza", has two schools!). My naive suggestion before was to use the extend function instead, which combines lists. Compare the following lines of code:

# Appending a list to another list
>>> my_dogs = ['fido', 'spot', 'spike']
>>> my_dogs.append(['spike', 'klaus'])
>>> my_dogs
['fido', 'spot', 'spike', ['spike', 'klaus']]
# Oh no, a list of strings and lists!

# Extending a list with another list
>>> my_dogs = ['fido', 'spot', 'spike']
>>> my_dogs.extend(['spike', 'klaus'])
>>> my_dogs
['fido', 'spot', 'spike', 'spike', 'klaus']
# A list of only strings, yay!

This would have worked fine, except you only care about unique schools. In order to make sure that you are only adding new schools, there is a convenient thing you can do in python after you have built your list of strings:

# http://stackoverflow.com/questions/7961363/python-removing-duplicates-in-lists?answertab=votes#tab-top
>>> my_dogs = list(set(my_dogs))
>>> my_dogs
['fido', 'spot', 'spike', 'klaus']

A set is a list that has no duplicates. So by passing in a list (such as schoollist) to the set function, and then converting that set back to a list, you remove all duplicates. We don't cover sets in this course, so let me know if this was confusing - there are other ways to accomplish this (a nested for loop) that might make more sense.

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2) Line 22's "Get a list of schools from the user" psuedo-code:

The following psuedo-code should map almost 1-1 with the correct python code:

all_choice = ask the user if they want to compare all colleges
if all_choice is "yes"
    schoolnames = schoollist
otherwise
    continue_choice = "yes"
    schoolnames is an empty list
    while continue_choice is "yes"
        school_choice = ask the user for their choice
        use difflib to make sure that the school_choice is in the list of schoollist
        if it is
            append the school_choice to the list of schoolnames
            continue_choice = ask the user if they want to continue
            optionally, check that the continue_choice was either "yes" or "no" and print out an error message if it isn't
        otherwise
            print out an error message, and let the loop continue again

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3) Line 62's "Show businesses with high reviews psuedo-code:

continue_choice = "yes"
while continue_choice is "yes"
    school_choice = ask the user for their choice
    use difflib to make sure that the school is in the list of school names
    if it is
        for business in all_businesses:
            for school in business['schools']:
                if school == school_choice:
                    if business['stars'] >= 4:
                        print business['name']
        continue_choice = ask the user if they want to continue
        optionally, check that the continue_choice was either "yes" or "no" and print out an error message if it isn't
    otherwise
        print out an error message, and let the loop continue again