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SteelK
Dec 9th, 2016
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C++
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long
double
yk
=
0
, sum
=
0
, iter
=
0
, mas2
[
100
]
;
while
(
iter
<=
k
)
{
for
(
int
i
=
0
;
i
<=
k
;
i
++
)
{
sum
+
=
mas
[
1
]
[
i
]
;
}
mas2
[
i
]
=
(
(
b
-
a
)
/
n
)
*
sum
;
iter
++
;
}
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