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May 23rd, 2018
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  1. datepart(year, c.cko_date)
  2.  
  3. select datepart(year, getdate())
  4.  
  5. datepart(year, c.cko_date + 25567)
  6.  
  7. --declare an integer representing the number of days since 1970-01-01
  8. DECLARE @days_since_unix_epoch int = 17674; --2018-05-23
  9. --show the datetime value in UTC
  10. SELECT UTC = CONVERT(datetime, @days_since_unix_epoch + 25567)
  11. --show the datetime value in North American CDT
  12. , CDT = CONVERT(datetime, @days_since_unix_epoch + 25567) - CONVERT(datetime, '05:00:00');
  13.  
  14. 1970-01-01 00:00:00
  15.  
  16. SELECT [1ms] = CONVERT(datetime, '2018-05-22 00:00:00.001')
  17. , [2ms] = CONVERT(datetime, '2018-05-22 00:00:00.002')
  18. , [3ms] = CONVERT(datetime, '2018-05-22 00:00:00.003')
  19.  
  20. datetime2
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