79

int n; cin >> n;
string s; cin >> s;
bool o = false, e = false;
for (int i = n&1^1; i < n; i += 2)
    o |= ((s[i]&1) == 1),
    e |= ((s[i]&1) == 0);
if ((n&1) && o || !e)
    cout << "1\n";
else
    cout << "2\n";