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Jan 13th, 2024
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C++ 1.95 KB | None | 0 0
  1. #include<iostream>
  2. #include<cstdio>
  3. #include<algorithm>
  4. #include<cstring>
  5. typedef long long ll;
  6. const ll mod = 1000000007;
  7. template <typename T> T Add(T x, T y) { return (x + y >= mod) ? (x + y - mod) : (x + y); }
  8. template <typename T> T cAdd(T x, T y) { return x = (x + y >= mod) ? (x + y - mod) : (x + y); }
  9. template <typename T> T Mul(T x, T y) { return x * y % mod; }
  10. template <typename T> T Mod(T x) { return x < 0 ? (x + mod) : x; }
  11. template <typename T> T Max(T x, T y) { return x > y ? x : y; }
  12. template <typename T> T Min(T x, T y) { return x < y ? x : y; }
  13. template <typename T> T Abs(T x) { return x < 0 ? -x : x; }
  14. template <typename T> T chkmax(T &x, T y) { return x = x > y ? x : y; }
  15. template <typename T>
  16. T &read(T &r) {
  17.     r = 0; bool w = 0; char ch = getchar();
  18.     while(ch < '0' || ch > '9') w = ch == '-' ? 1 : 0, ch = getchar();
  19.     while(ch >= '0' && ch <= '9') r = (r << 3) + (r <<1) + (ch ^ 48), ch = getchar();
  20.     return r = w ? -r : r;
  21. }
  22. ll qpow(ll x, ll y) {
  23.     ll sumq = 1;
  24.     while(y) {
  25.         if(y & 1) sumq = sumq * x % mod;
  26.         x = x * x % mod;
  27.         y >>= 1;
  28.     }
  29.     return sumq;
  30. }
  31. const int N = 110;
  32. int n, m;
  33. int len[N], f[N][N], s[N][N][N];
  34. signed main() { //freopen("in.txt", "r", stdin); freopen("out.txt", "w", stdout);
  35.     read(n); read(m);
  36.     for(int i = 1; i <= n; ++i) {
  37.         read(len[i]);
  38.         for(int j = 1; j <= len[i]; ++j) {
  39.             int x, y; read(x); read(y);
  40.             for(int k = x; k <= y; ++k)
  41.                 ++s[k][x][y];
  42.         }
  43.     }
  44.     for(int k = 1; k <= m; ++k) {
  45.         for(int l = m; l; --l)
  46.             for(int r = 1; r <= m; ++r)
  47.                 s[k][l][r] += s[k][l][r-1];
  48.         for(int l = m; l; --l)
  49.             for(int r = 1; r <= m; ++r)
  50.                 s[k][l][r] += s[k][l+1][r];
  51.     }
  52.     for(int k = 1; k <= m; ++k) f[k][k] = s[k][k][k] * s[k][k][k];
  53.     for(int len = 1; len < m; ++len)
  54.         for(int i = 1; i + len <= m; ++i) {
  55.             int j = i + len;
  56.             for(int k = i; k <= j; ++k) f[i][j] = Max(f[i][j], f[i][k-1] + s[k][i][j] * s[k][i][j] + f[k+1][j]);
  57.         }
  58.     printf("%d\n", f[1][m]);
  59.     return 0;
  60. }
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