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Jul 21st, 2019
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  1. set TASKS;
  2. set PROCS;
  3.  
  4. param cost {TASKS};
  5. param dist {PROCS};
  6.  
  7. var x {i in PROCS, j in TASKS}, binary;
  8.  
  9. minimize obj: sum{i in PROCS, j in TASKS} x[i,j]*dist[i]*cost[j];
  10.  
  11. subject to max_mapped:
  12. sum{i in PROCS, j in TASKS} x[i,j] = 7;
  13. subject to every_task:
  14. for {j in TASKS}: sum{i in PROCS} x[i,j] = 1;
  15. subject to only_one:
  16. for {i in PROCS}: sum{j in TASKS} x[i,j] <= 1;
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