Modify Boolean Matrix

#Methodd 1:TC = O(N*M) and space complexity O(N+M)
#LOGIC:we sill store all the rows in map which have 1 atleast one and same for col.
#after that traverse the matrix,make the (i,j) box=1 if i is in row map,or j is in col map.
def booleanMatrix_method1(matrix):
    row, col = {}, {}
    for i in range(len(matrix)):
        for j in range(len(matrix[i])):
            if matrix[i][j] == 1:
                row[i] = 1
                col[j] = 1

    for i in range(len(matrix)):
        for j in range(len(matrix[i])):
            if matrix[i][j] == 0 and (row.get(i, 0) or col.get(j, 0)):
                matrix[i][j] = 1


#Method 2:
#TC O(N*M) space O(1)
#we did same as the method 1 ,we wanted to store the row and col having one at some place,so we will store at
#oth row and oth col and one more thing to find,if 0th row and oth col will be all 1 or not that we did using
#row and col variable and after that traverse the full array and made those (i,j) box 1 whose i is present in
#0th row and whose j is present in 0th col.
#and finally if first row should be 1 then put 1 and same for col.
class Solution:
    #Function to modify the matrix such that if a matrix cell matrix[i][j]
    #is 1 then all the cells in its ith row and jth column will become 1.
    def booleanMatrix(self, matrix):
        row = False
        col = False

        for i in range(len(matrix)):
            for j in range(len(matrix[i])):
                if matrix[i][j] == 1 and i == 0:
                    row = True  #if i==0,means 1st full row should be 1
                if matrix[i][j] == 1 and j == 0:
                    col = True  #if j==1,means 1st full col should be 1
                if matrix[i][j] == 1:
                    matrix[0][j] = 1                     #marked the column which should be 1
                    matrix[i][0] = 1                     #marked the row which should be 1

        for i in range(1, len(matrix)):
            for j in range(1, len(matrix[i])):
                if matrix[i][j] == 0 and (matrix[0][j] == 1 or matrix[i][0] == 1):
                    matrix[i][j] = 1

        for i in range(len(matrix)):
            for j in range(len(matrix[i])):
                if row:
                    matrix[0][j] = 1
                if col:
                    matrix[i][0] = 1