findnumpty.py

# Probably not the best quality code
# but it's fun, so who cares :)
# Written by Tiin57
# Don't remove that, okay thanks

import requests, re
from lxml import html
from random import randint

template = '''
<center>
    <span id="%s" class="%s" style="%s font-size: 96px;">%s<br></span><br>
    <span style="font-size: 36px;">is a numpty</span>
</center>\n
'''

whitelist = ('Tiin57', 'clolin01', 'Trex')
def ternary(cond, iftrue, iffalse):
    if (cond):
        return iftrue
    else:
        return iffalse
def check_text(ele):
    if ele.text != None:
        scheck = ele.getparent().get('style')
        return [ele.text, ternary(scheck, scheck, ele.get('style')), ele.getparent().getparent().tag == 'strong']
    if len(ele.getchildren()) != 0:
        return check_text(ele.getchildren()[0])
def get_numpty(numpties):
    n = numpties[randint(0, len(numpties) - 1)]
    if n[0] in whitelist:
        return get_numpty(numpties)
    return n
def index(req):
    findnumpty(req)
def findnumpty(req):
    req.content_type = 'text/html'
    req.write('''
        <style>
        body {
            font-family: Tahoma, Geneva, Sans-Serif;
            font-size: 13px;
        }
        .bold {
            font-weight: bold
        }
        </style>
        ''')
    tree = html.fromstring(requests.get('http://forums.hexteria.com/showteam.php').text)
    elements = []
    numpties = []
    for i in tree.cssselect('td[width="60%"]'):
        elements.append(i)
    for i in elements:
        x = check_text(i)
        if x == None:
            continue
        text = x[0]
        style = x[1]
        isstrong = x[2]
        if text == '' or text.startswith(' start: ') or re.match(r'/[\s]+/', text):
            continue
        numpties.append(x)
    winner = get_numpty(numpties)
    req.write('<title>%s is a numpty</title>' % winner[0])
    req.write(template % (winner[0], ternary(winner[2], 'bold', ''), winner[1], winner[0]))