from datetime import datetime

def calculate_stardate():
    c = 48315
    b = 2371
    y = datetime.utcnow().year
    n = 366 if is_leap_year(y) else 365  # Define `is_leap_year` function to check leap year
    d = datetime.utcnow().timetuple().tm_yday
    star_date = c + (1000 * (y - b)) + (int(1000 / n * (d - 1)))
    day_progress = datetime.utcnow().timeofday().total_seconds() / 86400  # Convert to fraction of a day
    formatted_stardate = f"{star_date}.{str(day_progress)[2:5]}"  # Adjust slice to match precision
    return formatted_stardate

def is_leap_year(year):
    return year % 4 == 0 and (year % 100 != 0 or year % 400 == 0)