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Feb 24th, 2020
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  1. f :: Int -> [a] -> [a]
  2. f nr (x:xs) = g 1 nr (x:xs)
  3. where
  4. g _ _ []=[]
  5. g i nr (x:xs)
  6. |(mod i nr==0)=g(i+1) nr xs
  7. |otherwise = x:g(i+1) nr xs
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