CC Redstone And Gate

local tArgs = {...}

if #tArgs ~= 1 then
   print("Usage: andGate <sides>")
   print("  -- the left of the screen is A, the screen is B")
   print("  -- the right of the screen is C, the back is output")
   print("  -- if sides is 1, the system will check A and B")
   print("  -- if sides is 2, the system will check B and C")
   print("  -- if sides is 3, the system will check A and C")
   print("  -- if sides is 4, the system will check A, B, and C")
   print("  -- all inputs must be true(active) for the output to be true")
   return
end

local sides = tonumber(tArgs[1])

if sides < 1 then
  sides = 1
elseif sides > 4 then
  sides = 4
end

local function testTwo(side1, side2)
  if (((redstone.getInput(side1) == true) or (redstone.getBundledInput(side1) > 0)) and
     ((redstone.getInput(side2) == true) or (redstone.getBundledInput(side2) > 0))) then
       redstone.setOutput("back",true)
       redstone.setBundledOutput("back",255)
  else
     redstone.setOutput("back",false)
     redstone.setBundledOutput("back",0)
  end
end

while true do
  if (sides == 1) then
    testTwo("left","front")
  end

  if (sides == 2) then
    testTwo("right","front")
  end

  if (sides == 3) then
    testTwo("right","left")
  end

  if (sides == 4) then
    if (((redstone.getInput("left") == true) or (redstone.getBundledInput("left") > 0)) and
       ((redstone.getInput("front") == true) or (redstone.getBundledInput("front") > 0)) and
       ((redstone.getInput("right") == true) or (redstone.getBundledInput("right") > 0))) then
         redstone.setOutput("back",true)
         redstone.setBundledOutput("back",255)
    else
      redstone.setOutput("back",false)
      redstone.setBundledOutput("back",0)
    end
  end


  os.pullEvent("redstone")

end