Sum of perfect squares

a=int(input())
lst=[]
def square(n):
    i=0
    while True:
        if i**2>n:
            lst.append(i-1)
            return square(n-(i-1)**2)
        if ((n-i**2)**0.5)%1==0:
            if i!=0:
                lst.append(i)
            lst.append(int((n-i**2)**0.5))
            break
        i+=1
square(a)
print(*lst)